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bgonçalves
Brazil
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June 9, 2010
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how to use the statistical universe in lotteries?
Is the hot-cold parameter ideal, or do we need to cross more strategies?

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Florida Dump Water
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June 5, 2002
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how to use the statistical universe in lotteries?
Is the hot-cold parameter ideal, or do we need to cross more strategies?

I don’t touch the “statistical universe” thingie beyond saying it’s an elliptoid spheroid full of combinations.

Hot cold is not ideal, you want hot, average, cold and it’s just a filter set among many that improve your chances when correct and eliminate them when wrong.

BobP Quality

The avatar stat - animation sphere.gif

700 yrs light West in the center of the Galaxy Way
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I don’t touch the “statistical universe” thingie beyond saying it’s an elliptoid spheroid full of combinations.

Hot cold is not ideal, you want hot, average, cold and it’s just a filter set among many that improve your chances when correct and eliminate them when wrong.

BobP Quality

I agree! Don’t think he can say any better. !! .. But be careful, there are some here that would make you demonstrate that, with 1 hand tied behind your back, both eyes closed, while using a broken calculator ..! ! .. Related to some sorta ”Challenge “ stuff .. !! Blue Think

MATHEMATICS… The end Stochastic border …

These are the lottery trips to Stat $ pal.. !!

The mission is continuous, ..seek the laws of “Math Probability“…

a master its rules for invoking… conquer EVERYTHING Great skin .. !!

… To go boldly, … Where no player goes before… !!

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Three groups? The winning numbers can be from one, two or all three groups. If you add more models, they must all have reason to win the first prize. Would it be simpler to choose the correct numbers immediately and not think about patterns?

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bgonçalves
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hello spell, but defaults is a way to reduce and then filter by column, well then we can use the veen graph, to avoid conflict of the filters?

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Belgium
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John Venn’s? Can you draw it in your pro paint or in paint.exe?

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Belgium
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hello spell, but defaults is a way to reduce and then filter by column, well then we can use the veen graph, to avoid conflict of the filters?

You can do the opposite, you filter first and reduce afterwards by picking the line to run a program to maintain a protection, as you probably fail to do well by picking. And you forget about the graph.

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bgonçalves
Brazil
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June 9, 2010
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hello speller, to avoid conflicts in the lottery filters you must create the veen board! OK! in fact speller is a good job, it is to make the vein graph to avoid conflict of the lottery filters

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Belgium
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I want to see your veenbes graph on a case out.

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bgonçalves
Brazil
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June 9, 2010
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Enter A: number divisible by 2
2,4,6,8,10,12,14,16,18,20,22,24

Set B: number divisible by 3
3,6,9,12,15,18,21,24

Overlap:
6,12,18,24

en.wikipedia.org/wiki/Venn_diagram
pt.wikipedia.org/wiki/Diagrama_de_Venn

Using two filters and a 2-circle vein diagram, you will need three numbers:
The hit ratio of the first filter, the hit ratio of the second filter, and the hit ratio of both filters when used together.

The first proportion goes to one crescent, the second goes to the other crescent, and the third number goes to the overlapping oval.

How the overlap is compared compared to the mathematical overlap is expected to tell you whether to use these two filters together or at all.

: teach: Example: Filter A hit ratio 0.5 and filter B hit ratio 0.333.
If the combined (oval) hit ratio is less than 1/6, the two filters should not be used together.

speller, my lottery (one of them) used from 01 to 25 where 15 numbers (lotofacil) are drawn, can you put some filters on the graph of veen?

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bgonçalves
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https://en.wikipedia.org/wiki/File:Venn3tab.svg

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Belgium
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A = {2; …}

B = {3; …}

A ∩ B = {6; …}

6 mod 2 == 0 && 6 mod 3 == 0

6 ≡ …

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“Speller, my lottery (one of them) used from 01 to 25 where 15 numbers (lotofacil) are drawn, you can put some filters on the graph of veenbes ¿”

You need 15 numbers. You have a B union so far. Do you have 15 numbers Do you

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Florida Dump Water
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Three groups? The winning numbers can be from one, two or all three groups. If you add more models, they must all have reason to win the first prize. Would it be simpler to choose the correct numbers immediately and not think about patterns?

Agree it is possible all the numbers win all cases from one, two or all three groups, even if it is 2-2-2 most likely.

http://web.archive.org/web/20050126053842/http://www.geocities.com/wallstreet/7746/hwc.html

BobP Quality

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Belgium
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6/45

3 groups of 15 numbers.

15 15 15 Combine Combine Combine Product * Order p 1 / p
2 2 2 105 105 105 1157625 0.14 7.04
3 2 1 455 105 15 4299750 0.53 1.89
3 3 0 455 455 1 621075 0.08 13.11
4 1 1 1365 15 15 921375 0.11 8.84
4 2 0 1365 105 1 859950 0.11 9.47
5 1 0 3003 15 1 270270 0.03 30.14
6 0 0 5005 1 1 15015 0 542.46
Check out SUMM: 8145060

Rounded fractions: 0.00

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